Two tiny spheres carrying charges 1.8μCand2.8μC are located at 40 cm apart. The potential at the mid-point of the line joining the two charges is
3.8×104V
2.1×105V
4.3×104V
6.3×105V
The correct Answer is:B
here, q1=1.8μC=1.8×10−6C,q2=2.8μC=2.8×10−6C
Distance between the two spheres = 40 cm = 0.4 cm
For the mid-point r1=r2=0.402=0.2m
Potential at O, V=14πε0[q1r1+q2r2]=9×109(1.8+2.8)×10−60.2
=2.1×105V
Related Playlists
- BOOK - NCERT FINGERTIPSCHAPTER - ELECTROSTATIC POTENTIAL AND CAPACITANCE EXERCISE - Equipotential Surfaces9videos
ELECTROSTATIC POTENTIAL AND CAPACITANCE
- BOOK - NCERT FINGERTIPSCHAPTER - ELECTROSTATIC POTENTIAL AND CAPACITANCE EXERCISE - Potential Energy As A System Of Charges4videos
ELECTROSTATIC POTENTIAL AND CAPACITANCE
- BOOK - NCERT FINGERTIPSCHAPTER - ELECTROSTATIC POTENTIAL AND CAPACITANCE EXERCISE - Potential Due To An Electric Dipole5videos
ELECTROSTATIC POTENTIAL AND CAPACITANCE
- BOOK - NCERT FINGERTIPSCHAPTER - ELECTROMAGNETIC WAVESEXERCISE - Assertion And Reason15videos
ELECTROMAGNETIC WAVES
- BOOK - NCERT FINGERTIPSCHAPTER - MAGNETISM AND MATTER EXERCISE - Assertion And Reason15videos
MAGNETISM AND MATTER
Similar Questions
Two tiny spheres carrying charges 1.5μC and 2.5μC are located 30 cm apart. Find the potential
(a) at the mid-point of the line joining the two charges and
(b). At a point 10 cm from this mid-point in a plane normal to the line and passing through the mid-point.View SolutionTwo tiny spheres carrying charges 1.5μCand2.5μC are located 30 cm apart. Find the potential and electric field:
(a) at the mid-point of the line joining the two charges, and
(b) at a point 10 cm from this mid-point in a plane normal to the line and passing through the mid point.View SolutionTwo charges -4 C and +4 C are placed at 10 cm apart. The potential at the center of the line joining two charges is
View SolutionTwo tiny spheres carrying charges 1.5μC and 2.5μC are located 30 cm apart. Find the potential
(a) at the mid-point of the line joining the two charges and
(b). At a point 10 cm from this mid-point in a plane normal to the line and passing through the mid-point.View SolutionTwo charges −10C and +10C are placed 10 cm apart. Potential at the centre of the line joining the two charges is
View SolutionTwo point charges of +10μC and +20μC are placed in free space 2 cm apart. Find the electric potential at the middle point of the line joining the two charges.
View SolutionTwo charges +5μC and +10μC are placed 20cm apart. The net electric field at the mid-point between the two charges is
View SolutionTwo positive charges of 1mu Cand2 mu C are placed 1 metre apart. The value of electric field in N/C at the middle point of the line joining the charge will be :
View SolutionTwo point charges qA=3μCandqB=−3μC are located 20 cm apart in vacuum.
What is the electric field at the midpoint O of the line AB joining the two charges?
If a negative test charges of magnitude 1.5×10−9C
(##U_LIK_SP_PHY_XII_C01_E01_008_Q01.png" width="80%">View SolutionTwo electric charges of 9μCand−3μC are placed 0.16m apart in air. There are two points A and B on the line joining the two charges at distance of (1) 0.04m from −3μC and in between the charges and (ii) 0.08 m from −3μC and out side the two charges. The potentials at A and B are
View Solution