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Two tiny spheres carrying charges 1.8μCand2.8μC are located at 40 cm apart. The potential at the mid-point of the line joining the two charges is

A

3.8×104V

B

2.1×105V

C

4.3×104V

D

6.3×105V

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The correct Answer is:B


here, q1=1.8μC=1.8×106C,q2=2.8μC=2.8×106C
ocr_image
Distance between the two spheres = 40 cm = 0.4 cm
For the mid-point r1=r2=0.402=0.2m
Potential at O, V=14πε0[q1r1+q2r2]=9×109(1.8+2.8)×1060.2
=2.1×105V

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Updated on:21/07/2023

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