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Two capacitors of capacitance 600 pF and 900 pF are connected in series across a 200 V supply .Calculate the effective capacitance of the combination.

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Answer Text

Solution :
Given: `C_1`=600 pF , `C_2` =900 pF <br> V=200V <br> `1/C_S=1/C_1+1/C_2=(C_1+C_2)/(C_1+C_2)` <br> `C_S=(C_1C_2)/(C_1+C_2)=(600xx900)/(600+900)=(54xx10^4)/(15xx10^2)=5400/15`=360 pF <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SPH_PHY_HND_BOK_PUC_MQP_01_E01_033_S01.png" width="80%">

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