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Three capacitors of capacitance 1 muF, 2muF and 3 muF are connected in series and a potential difference of 11 V is applied across the combination. Then, the potential difference across the plates of 1 muF capacitor is

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Answer Text

`2 V``4 V``1 V``6 V`

Answer :
D
Solution :
Equivalent capacitance `(1)/(C_(eq)) = (1)/(1) + (1)/(2) + (1)/(3)` <br> `rArr C_(eq) = (6)/(11) muF` <br> Charge supplied from battery `Q = (6)/(11) xx 11 = 6muC` <br> Hence potential difference across `2 muF` capacitor <br> `= (6)/(1) = 6V`

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