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Three capacitors each of capaitance 9pF are connected in series. <br> (a) What is the total capacitance of the combination ? <br> (b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply ?

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Solution :
(a) `(1)/(C_s)=(1)/(9)+(1)/(9)+(1)/(9)=(3)/(9)=(1)/(3),C_s=3pF` <br> (b) P.d across each capacitor `=(V)/(3)=(120)/(3)=40V`.

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