The value of u so that the ball reaches at point A (g = 10m/s2) A u 45° 20m 10m -15m->

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Updated on:21/07/2023

Class 12 PHYSICS NONE

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Question 1 - Select One
A boy throws a ball upward with velocity $v_{0} = 20 m / s$ . The wind imparts a horizontal acceleration of $4 m / s^{2}$ to the left. The angle $θ$ at which the ball must be thrown so that the ball returns to the boy's hand is : $(g = 10 m s^{- 2})$
A ${tan}^{- 1} (1.2)$
B ${tan}^{- 1} (0.2)$
C ${tan}^{- 1} (2)$
D ${tan}^{- 1} (0.4)$
Question 1 - Select One
A ball of mass 400 gm is dropped from a height of 5 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical velocity of 20 m/s. The time for which the ball remains in contact with the bat is $(g = 10 m / s^{2})$
A0.12 s
B0.08s
C0.04 s
D12s
Question 1 - Select One
A ball of mass 50 g is dropped from a height of 20 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 200 N, so that it attains a vertical height of 45 m. The time for which the ball remains in contact with the bat is [Take $g = 10 m / s^{2}]$
A $1 / 10^{t h}$ of a second
B $1 / 40^{t h}$ of a second
C $1 / 80^{t h}$ of a second
D $1 / 120^{\circ}$ of a second
Question 1 - Select One
A ball of the mass 400gm is dropped from a height of 5m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100N so that it attains a vertical height of 20m. The time for which the ball remains in contect with the bat is [ $g = 10 m / s^{- 2}]$
A $0.12 s$
B $0.08 s$
C $0.04 s$
D $12 s$
Question 1 - Select One
If a ball is thrown vertically upwards with a velocity of $40 m / s$ , then velocity of the ball after $2 s$ will be $(g = 10 m / s^{2})$
A $15 m / s$
B $20 m / s$
C $25 m / s$
D $28 m / s$
Question 1 - Select One
A ball of mass 400 gm is dropped from a height of 5 m . A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical height of 20 m . The time for which the ball remains in contact with the bat is $[g = 10 m / s^{2}]$
A $0.12 s$
B $0.08$ s
C $0.04$ s
D12 s
Question 1 - Select One
A ball is throw vertically upward. It has a speed of $10 m / s$ when it has reached one half of its maximum height. How high does the ball rise ? (Taking $g = 10 m / s^{2}$ ).
A15 m
B10 m
C20 m
D5 m

The value of u so that the ball reaches at point A (g = 10m/s2) A u 45° 20m 10m -15m->

Similar Practice Problems

A boy throws a ball upward with velocity $v_{0} = 20 m / s$ . The wind imparts a horizontal acceleration of $4 m / s^{2}$ to the left. The angle $θ$ at which the ball must be thrown so that the ball returns to the boy's hand is : $(g = 10 m s^{- 2})$

A ball of mass 400 gm is dropped from a height of 5 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical velocity of 20 m/s. The time for which the ball remains in contact with the bat is $(g = 10 m / s^{2})$

A ball of mass 50 g is dropped from a height of 20 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 200 N, so that it attains a vertical height of 45 m. The time for which the ball remains in contact with the bat is [Take $g = 10 m / s^{2}]$

A ball of the mass 400gm is dropped from a height of 5m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100N so that it attains a vertical height of 20m. The time for which the ball remains in contect with the bat is [ $g = 10 m / s^{- 2}]$

If a ball is thrown vertically upwards with a velocity of $40 m / s$ , then velocity of the ball after $2 s$ will be $(g = 10 m / s^{2})$

A ball of mass 400 gm is dropped from a height of 5 m . A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical height of 20 m . The time for which the ball remains in contact with the bat is $[g = 10 m / s^{2}]$

A ball is throw vertically upward. It has a speed of $10 m / s$ when it has reached one half of its maximum height. How high does the ball rise ? (Taking $g = 10 m / s^{2}$ ).

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The value of u so that the ball reaches at point A (g = 10m/s2) A u 45° 20m 10m -15m->

Similar Practice Problems

A boy throws a ball upward with velocity v0=20m/s. The wind imparts a horizontal acceleration of 4m/s2 to the left. The angle θ at which the ball must be thrown so that the ball returns to the boy's hand is : (g=10ms−2)

A ball of mass 400 gm is dropped from a height of 5 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical velocity of 20 m/s. The time for which the ball remains in contact with the bat is (g=10m/s2)

A ball of mass 50 g is dropped from a height of 20 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 200 N, so that it attains a vertical height of 45 m. The time for which the ball remains in contact with the bat is [Take g=10m/s2]

A ball of the mass 400gm is dropped from a height of 5m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100N so that it attains a vertical height of 20m. The time for which the ball remains in contect with the bat is [g=10m/s−2]

If a ball is thrown vertically upwards with a velocity of 40m/s, then velocity of the ball after 2s will be (g=10m/s2)

A ball of mass 400 gm is dropped from a height of 5 m . A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical height of 20 m . The time for which the ball remains in contact with the bat is [g=10m/s2]

A ball is throw vertically upward. It has a speed of 10m/s when it has reached one half of its maximum height. How high does the ball rise ? (Taking g=10m/s2).

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A boy throws a ball upward with velocity $v_{0} = 20 m / s$ . The wind imparts a horizontal acceleration of $4 m / s^{2}$ to the left. The angle $θ$ at which the ball must be thrown so that the ball returns to the boy's hand is : $(g = 10 m s^{- 2})$

A ball of mass 400 gm is dropped from a height of 5 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical velocity of 20 m/s. The time for which the ball remains in contact with the bat is $(g = 10 m / s^{2})$

A ball of mass 50 g is dropped from a height of 20 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 200 N, so that it attains a vertical height of 45 m. The time for which the ball remains in contact with the bat is [Take $g = 10 m / s^{2}]$

A ball of the mass 400gm is dropped from a height of 5m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100N so that it attains a vertical height of 20m. The time for which the ball remains in contect with the bat is [ $g = 10 m / s^{- 2}]$

If a ball is thrown vertically upwards with a velocity of $40 m / s$ , then velocity of the ball after $2 s$ will be $(g = 10 m / s^{2})$

A ball of mass 400 gm is dropped from a height of 5 m . A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical height of 20 m . The time for which the ball remains in contact with the bat is $[g = 10 m / s^{2}]$

A ball is throw vertically upward. It has a speed of $10 m / s$ when it has reached one half of its maximum height. How high does the ball rise ? (Taking $g = 10 m / s^{2}$ ).