The value of u so that the ball reaches at point A (g = 10m/s2) A u 45° 20m 10m -15m->

A body is projected obliquely at 30^(0) with the horizontal .The time when angular momentum about point of projection is maximum in sec is --------- if (u=10m/s g=10m/s^(2)

A ball is projected from ground with a speed of 20ms^(-1) at an angle of 45^(@) with horizontal.There is a wall of 25m height at a distance of 10m from the projection point. The ball will hit the wall at a height of

A ball of mass 160 g is thrown up at an angle of 60^(@) to the horizontal at a speed of 10ms^(-1) . The angular momentum of the ball at highest point of the trajectory with respect to the point from which the ball is thrown is nearly (g=10ms^(2))

A ball of mass 160 g is thrown up at an angle of ${60}^{\circ }$ to the horizontal at a speed of $10m{s}^{-1}$. The angular momentum of the ball at the highest point of the trajectory with respect to the point from which the ball is thrown is nearly $(g=10m{s}^{-2})$

एक क्रिकेट गेंद को 20m की ऊंचाई से गिराया जाता है ।
(a) पृथ्वी की सतह पर पहुंचने के समय वेग की गणना करें।
(b) पृथ्वी की सतह तक पहुंचने में लगा समय ज्ञात करें । [$g=10m/{\sec }^2$ ले]

Ball of mass 5.0 kilograms moving at 20m/s collides with ball B of unknown mass moving at 10m/s in the same direction . After collision ball A moves at 10m/s an ball B at 15m/s , both still in the same direction. What is the mass of ball B?

A particle is projected upwards with initial velocity u. assume acceleration due to gravity is 10m//s^(2) . It is found that particle covers 5m in last second before reaching the maximum height. What can be the possible value of u?

A ball is dropped from a height of 20m. it rebounds to a height on 10m. Calculate the loss of energy of the ball