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Solution :

From parallax method we can say <br> `theta = b//D`, where b = baseline, D = distance of distant object or star <br> Since, `theta=1" (s)` and `n=3xx10^(11) m` <br> `D=b//20=3xx10^(11)//2xx4.85xx10^(-6) m` <br> or `D=3xx10^(11)//9.7xx10^(-6) m=30xx10^(16)//9.7 m` <br> `3.09xx10^(16)m=3xx10^(16) m`.Related Video

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