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The photograph fo a house occupies an area of 1.7cm^2 on a 35 slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55m^2 What is the liner magnification of the projector screen arrangement?

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Solution :
Area of the house on the slide =`1.75 cm^(2)` <br> Area of the image of the house formed on the screen `=1.55 m^(2)` <br> `=1.55 xx10^(4) cm^(2)` <br> Arial magnification, `m_(a) =("Area of image ")/("area of object") =1.55/1.75 xx10^(4)` <br> `:.` Linear magnification , `m_(1)=sqrt(m_(a))` <br> `=sqrt(1.55/1.76xx10^(4))=94.11`

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