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The handle of a door is at a distance 40 c m from axis of rotation. If a force 5 N is applied on the handle in a direction 30 with plane of door, then the torque is

A

0.8 N m

B

1 N m

C

1.6 N m

D

2 N m

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The correct Answer is:B


τ = r F sin θ

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Updated on:21/07/2023

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