The handle of a door is at a distance ${\displaystyle 40cm}$ from axis of rotation. If a force ${\displaystyle 5N}$ is applied on the handle in a direction ${\displaystyle {30}^{\circ }}$ with plane of door, then the torque is

Why the handles of the doors are at maximum distance from the hinges?

To push open a door, a person applies a force of 75 N on the handle of the door, at an angle of ${60}^{\circ }$ from the normal to its plane. If the handle is located at a distance of 80 cm from its hinge, find the torque applied by him.

A particle is at a distance r from the axis of rotation. A given torque $\tau$ produces some angular acceleration in it. If the mass of the particle is doubled and its distance from the axis is halved, the value of torque to produce the same angular acceleration is -

A force of $36N$ is applied to a particle located at $0.15m$ from the axis of rotation. What is the magnitude of the torque about this axis, if the angle between the direction of the applied force and radius vector is (a)${120}^{\circ }\left(b\right){45}^{\circ }$?

A force $\overrightarrow{F}=(\hat{i}+3\hat{j})N$ acts on a body at a point P, which is at a distance given by $\overrightarrow{r}=(3\hat{i}+\hat{j})m$ from the axis of rotation.
What is the direction of the torque acting on the body?

A : The moment of force is maximum for a point if force applied on it and its position vector w.r.t. the point of rotation are perpendicular.
R : The magnitude of torque is independent of the direction of application of force.

A nut cracker is used to crack a nut. In it nut is held in two arms at a distance 2 cm from the hinge and the handle of it is at a distance 25 cm from hinge. The force required to crack a walnut is 30 N. What is the minimum force required to crack it with the nut cracker.
[2.4 N]

The radius of a solid sphere I 40 cm. The radius of gyration when the axis of rotation is along a tangent in a plane in cm is

A disc of radius 10 cm can rotate about an axis passing through its centre and perpendicular to its plane. A force of 10 N is applied along the tangent in the plane of the disc. If the moment of inertia of the disc about its centre is $5kg{m}^2$, then the increase in the angular velocity of the disc in 10 s will be

A force $\overrightarrow{F}=(\hat{i}+3\hat{j})N$ acts on a body at a point P , which is at a distance , give by $\overrightarrow{r}=(3\hat{i}+\hat{j})$ m form the axis of rotation .
What is the direction of the torque acting on the body ?