logo
or
search
upload

The electric field intensity in free space at a distance 'r' outside a charged conducting sphere of radius 'R' in terms of surface charge density sigma is

Apne doubts clear karein ab Whatsapp par bhi. Try it now.
CLICK HERE

Loading DoubtNut Solution for you

Watch 1000+ concepts & tricky questions explained!

16.7 K+ views | 800+ people like this

   
Share
Share

Answer Text

`(sigma)/(epsi_(0))[(R)/(r)]^(2)``(epsi_(0))/(sigma)[(R)/(r)]^(2)``(R)/(r)[(sigma)/(epsi_0)]^(2)``(R)/(sigma)[(r)/(epsi_(0))]^(2)`

Answer :
A
Solution :
The electric field intensity at a point at a distance r outside <br> a charged conducting sphere is `E=(1)/(4piepsi_(0))(q)/(r^(2))` . .. (1) <br> where `r gt R`. <br> But surface charge density `(sigma)` of the sphere is <br> `sigma=(q)/(4piR^(2))" "therefore q=4piR^(2)sigma` <br> From (1), `E=(1)/(4piepsi_(0))(4piR^(2)sigma)/(r^(2)) =(sigma)/(epsi_(0))[(R)/(r)]^(2)`

Related Video

6:09

76.5 K+ Views | 56.8 K+ Likes

1:29

38.8 K+ Views | 1.9 K+ Likes

5:57

76.0 K+ Views | 3.8 K+ Likes

7:30

49.7 K+ Views | 32.8 K+ Likes

3:44

155.0 K+ Views | 10.4 K+ Likes

32.7 K+ Views | 1.6 K+ Likes

1:47

295.8 K+ Views | 14.7 K+ Likes

bottom open in app