The degree of association (α) is given by the expression
α=n(i−1)1−n
α=i(n−1)1+n
α=i(n+1)1−n
α=i(n+1)n−1
The correct Answer is:A
nA1 mole⇔An
1−α αn, Total=1−α+αn
∴i=1−α+αnor1−i=α−αn=α(1−1n)
=α(n−1n)
orα=n(n−1)(i−i)=n(i−1)(1−n)
Related Playlists
- BOOK - PRADEEPCHAPTER - SOLUTIONSEXERCISE - Competition (FOCUS) JEE (Main and Advanced)/Medical Entrance SPECIAL (II. Multiple Choice Question )7videos
SOLUTIONS
- BOOK - PRADEEPCHAPTER - SOLUTIONSEXERCISE - Competition (FOCUS) JEE (Main and Advanced)/Medical Entrance SPECIAL (III. Multiple Choice Question )13videos
SOLUTIONS
- BOOK - PRADEEPCHAPTER - SOLUTIONSEXERCISE - VALUE BASED QUESTIONS WITH ANSWERS7videos
SOLUTIONS
- BOOK - PRADEEPCHAPTER - REDOX REACTIONS EXERCISE - Assertion reason type question16videos
REDOX REACTIONS
- BOOK - PRADEEPCHAPTER - SOME BASIC CONCEPTS OF CHEMISTRYEXERCISE - Competition (FOCUS) JEE (Main and Advanced)/Medical Entrance SPECIAL (VIII. Assertion-Reason Type Questions)(Type II)13videos
SOME BASIC CONCEPTS OF CHEMISTRY
Similar Questions
The degree of association is given by the expression :
View SolutionFor the given electrolyte AxBy. The degree of dissociation 'α' can be given as:
View SolutionThe potential energy of a point particle is given by the expression V(x)=−αx+βsin(x/γ). A dimensionless combination of the constant α,β and γ is–
View SolutionThe degree of dissociation of PC15 (α) obeying the equilibrium, PC15⇔PC13+C12, is approximately related to the pressure at equilibrium by (given α<<1) :
View SolutionThe degree of dissociation of PCI5(α) obeying the equilibrium, PCI5⇔PCI3+CI2, is approximately related to the presure at equilibrium by (given α<<1):
View SolutionThe degree of dissociation (α) of a weak electrolyte, AxBy is related to van't Hoff's factor (i) by the expression:
View SolutionThe degree of dissociation (α) of a weak electrolyte AxBy is related to van't Hoff factor (i) by the expression
View SolutionThe degree of dissociation (α) of a weak electrolyte, AxBy is related to van't Hoff's factor (i) by the expression:
View SolutionShow that degree of dissociation (α) for the dissociation of PCl5 into PCl3 and Cl2 at pressure P is given by α=[kpP+kp]1/2
View SolutionFor a concentrated solution of a weak electrolyte, AxBy of concentration 'C', the degree of dissociation α is given by
View Solution