logo
or
search
upload

One mole of an ideal gas at NTP occupies 22.4 liters (molar volume). What is the ratio of molar volume to atomic volume to atomic volume of a mole of hydrogen ? Take size of hydrogen molecule to be 1 Å. Why is this ratio so large?

Apne doubts clear karein ab Whatsapp par bhi. Try it now.
CLICK HERE

Loading DoubtNut Solution for you

Watch 1000+ concepts & tricky questions explained!

17.2 K+ views | 800+ people like this

   
Share
Share

Answer Text

Solution :
Volume of one mole of ideal gas, `V_(g)` <br> `=22.4` litre `=22.4xx10^(-3) m^(3)` <br> Radius of hydrogen molecule `=1 A//2` <br> `=0.5 A=0.5xx10^(-10) m` <br> Volume of hydrogen molecule`=4//3 pi r^(3)` <br> `=4//3xx22//7(0.5xx10^(-10))^(3) m^(3)` <br> `=0.5238xx10^(-30) m^(3)` <br> One mole contains `6.023xx10^(23)` molecules. <br> Volume of one mole of hydrogen, `VH` <br> `=0.5238xx10^(-30)xx6.023xx10^(23) m^(3)=3.1548xx10^(-7) m^(3)` <br> Now `V_(g)//V_(H)=22.4xx10^(-3)//3.1548xx10^(-7)=7.1xx10^(4)` <br> The ratio is very large. This is because the interatomic separation in the gas is very large compared to the size of a hydrogen molecule.

bottom open in app