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Answer Text

`B/2``B/4``(B)/(sqrt(8))` `sqrt(8)B`

Answer :

CSolution :

The magnetic field at the centre of a circular coil of radius R carrying current I is <br> `B=(mu_(0)2piI)/(4piR)=(mu_(0I))/(2R)` <br> The magnetic field at a point along the axis at distance R from the centre of a circular coil of radius R carrying current I is <br> `B_(A)=(mu_(0)2piIR^(2))/(4pi(R^(2)+R^(2))^(3//2))=(mu_(0)I)/(2sqrt(8)R)=(B)/(sqrt(8))` Related Video