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is found experimentally that 13.6 eV energy is required to separate a hydrogen atom into a proton and an electron. Compute the orbital radius and the velocity of the electron in a hydrogen atom. Solution in Kannada

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Total energy of the electron in hydrogen atom is 13.6eV=13.6×1.6×1019J=2.2×1018J.
Thus, e28πε0r=2.2×1018J
This gives the orbital radius
r=e28πε0E=(9×109Nm2/C2)(1.6×1019×C)2(2)(2.2×1018J)
The velocity of the revolving electron can be computed with m=9.1×1031kg.
v=e4πε0mr=2.2×106m/s

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Updated on:21/07/2023

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