Figure shows the distance-time graph of three object A, B and C. Study the graph and answer the following questions : <br> (a) Which of the three is travelling the fastest ? <br> (b) Are all three ever at the same point on the road ? <br> ( c) How far has C travelld by when B passes A ? <br> (d) How far has B travelled by the time it passes C ?

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Solution :
(a) Object B <br> (b) No <br> (c ) 5.714 km <br> (d) 5.143 km <br> (a) Speed = `("Distance")/("Time")` <br> Slope of graph = `(y-"axis")/(x-"axis")=("Distance")/("Time")` <br> Therefore, Speed = slope of the graph <br> Since slope of object B is greater than objects A and C, it is travelling the fastest. <br> (b) All three objects A, B and C never meet at a single point. Thus, they were never at the same point on road. <br> (c ) <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_SCI_IX_C08_E01_033_S01.png" width="80%"> <br> 7 square box = 4 km ltBrgt `therefore` 1 square box = 4/7 km <br> C is 4 blocks away from origin therefore initial distance of C from origin = 16/7 km <br> Distance of C from origin when B passess A = 8 km <br> Thus, Distance travelled by C when B passes A = 8- 16/7=(56-16)/7=40/7=5.714 km <br> (d) <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_SCI_IX_C08_E01_033_S02.png" width="80%"> <br> Distance travelled by B by the time it passes C = 9 square boxes 9`xx`4/7 = 36/7 = 5.143 km

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