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Explain what would happen if a 3 mm thick mica sheet of (dielectric constant = 6) were inserted between the plates (a) while the voltage supply remained connected (b) after the supply was disconnected.

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Answer Text

Solution :
(a) dielectric constant of the mica sheet , k=6 <br> initial capacitance , C=1.771`xx10^(-11)F` <br> New capacitance , `C'=kC=6xx1.771xx10^(-11) =106 pf` <br> supply voltage , V=100 V <br> New charge, q'=C''V `=6xx1.771xx10^(-9) =1.06xx10^(-8) C` <br> potential across the paltes remain 100 v. <br> (b) dielectric constant , k=6 <br> initial capacitance, `C=1.771xx10^(-11)F` <br> New capacitance, C''=kC `=6xx1.771xx10^(-11) =106 pf` <br> if supply voltage is removed, then there will be no effect on the amount of charge in the plates. <br> Charge =`1.771xx10^(-9)C` <br> potential across the plates is given by <br> `:. V'=q/(C'')` <br> `=(1.771xx10^(-9))/(106xx10^(-12))` <br> `=16.7 V`

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