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Estimate the size of fluorine (liquid) molecule, given its atomic mass 19.01u and density 1.14xx10^(3) kgm^(-3).

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Answer Text

Solution :
Volume of a single molecule `=("mass of each molecule")/("density")` <br> `i.e. " " (4)/(3)piR^(3)=(12.01xx1.66xx10^(-27))/(2.22xx10^(3)),1mu=1.66xx10^(-27)kg` <br> `i.e. " " R_(3)=(3xx12.01xx1.66xx10^(-30))/(2.22xx4xx3.142)=2.144xx10^(-30).` <br> i.e. radius of each molecule `R=(2.144)^(1/3)xx10^(-10)m=1.289xx10^(-10)m.` <br> 1.289Å

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