Element 'X' , whose atoms have an outer - shell electronic configuration $n s^{2} n p^{4}$ , is most likely to react chemically to form ions, which have a charge of ________.

$2 +$

$1 +$

$1 -$

$2 -$

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The correct Answer is:D

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Step by step video, text & image solution for Element 'X' , whose atoms have an outer - shell electronic configuration ns^(2) np^(4), is most likely to react chemically to form ions, which have a charge of ________. by Chemistry experts to help you in doubts & scoring excellent marks in Class 11 exams.

Updated on:21/07/2023

Class 11 CHEMISTRY CHEMICAL BONDING AND MOLECULAR STRUCTURE

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Question 1 - Select One
The symbol of the element whose atoms have the outer most electronic configuration $2 s^{2} 2 p^{3}$ is
AN
BLi
CP
DNa
Question 1 - Select One
The atom having the valence shell electronic configuration $4 s^{2} 4 p^{2}$ would be in
Agroup-II A and period 3
Bgroup-II B and period 4
Cgroup-IV A and period 4
Dgroup-IV A and period 3
Question 1 - Select One
Elements with outer electron configuration ns2 np6 are:
AAlkaline earth metals
BTransition elements
CChalcogens
DNoble gases
Question 1 - Select One
The element having outer electronic configuration as $3 d^{6} 4 s^{2}$ is a:
Ametalloid
Bnon- metal
Ctransition metal
Dnoble gas
Question 1 - Select One
Ions which have the same electronic configuration are those of
ALithium and sodium
BSodium and potassium
Cpotassium and calcium
Doxygen and chlorine
Question 1 - Select One
The position of the element having outer electronic configuration $n s^{2} n p^{4} f or n = 3$ is
AII period fourth group
BIII period fourth group
CII period 16group
DIII period 16 group
Question 1 - Select One
He and Be both have the same outer electronic configuration like $n s^{2}$ type.
Statement-2 : Both are chemically inert.
AStatement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-4
BStatement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-4
CStatement-1 is True, Statement-2 is False
DStatement-1 is False, Statement-2 is True

Element 'X' , whose atoms have an outer - shell electronic configuration $n s^{2} n p^{4}$ , is most likely to react chemically to form ions, which have a charge of ________.

The correct Answer is:D

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Similar Practice Problems

The symbol of the element whose atoms have the outer most electronic configuration $2 s^{2} 2 p^{3}$ is

The atom having the valence shell electronic configuration $4 s^{2} 4 p^{2}$ would be in

Elements with outer electron configuration ns2 np6 are:

The element having outer electronic configuration as $3 d^{6} 4 s^{2}$ is a:

Ions which have the same electronic configuration are those of

The position of the element having outer electronic configuration $n s^{2} n p^{4} f or n = 3$ is

He and Be both have the same outer electronic configuration like $n s^{2}$ type.
Statement-2 : Both are chemically inert.

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TARGET PUBLICATION-NATURE OF CHEMICAL BOND-Evaluation test

Element 'X' , whose atoms have an outer - shell electronic configuration ns2np4, is most likely to react chemically to form ions, which have a charge of ________.

The correct Answer is:D

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The symbol of the element whose atoms have the outer most electronic configuration 2s22p3 is

The atom having the valence shell electronic configuration4s24p2 would be in

Elements with outer electron configuration ns2 np6 are:

The element having outer electronic configuration as 3d64s2 is a:

Ions which have the same electronic configuration are those of

The position of the element having outer electronic configuration ns2np4forn=3 is

He and Be both have the same outer electronic configuration like ns2 type. Statement-2 : Both are chemically inert.

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TARGET PUBLICATION-NATURE OF CHEMICAL BOND-Evaluation test

Element 'X' , whose atoms have an outer - shell electronic configuration $n s^{2} n p^{4}$ , is most likely to react chemically to form ions, which have a charge of ________.

The symbol of the element whose atoms have the outer most electronic configuration $2 s^{2} 2 p^{3}$ is

The atom having the valence shell electronic configuration $4 s^{2} 4 p^{2}$ would be in

The element having outer electronic configuration as $3 d^{6} 4 s^{2}$ is a:

The position of the element having outer electronic configuration $n s^{2} n p^{4} f or n = 3$ is

He and Be both have the same outer electronic configuration like $n s^{2}$ type.
Statement-2 : Both are chemically inert.