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Electron in hydrogen atom first jumps from third excited state to second excited state and then from second excited to the first excited state. The ratio of the wavelengths λ1,λ2 emitted in the two cases is

A

7/5

B

27/20

C

27/5

D

20/7

Text Solution
Verified by Experts

The correct Answer is:D


ocr_image
E1=hcλ1=13.6[1(3)21(4)2]........(i)
E2=hcλ2=13.6[1(2)21(3)2]......(ii)
dividing eq. (ii) by eq. (i)
λ1λ2=141919116=207

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Updated on:21/07/2023

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