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Due to 10 A of current flowing in a circular coil of 10 cm radius , the magnetic field produced at its centre is 3.14xx10^-3 Wb/m^2. The number of turns in the coil will be

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Answer Text

50001005025

Answer :
C
Solution :
`B=(mu_0nI)/(2A)` <br> `because n=(3.14xx10^-3xx2xx10^-1)/(4xxpixx10^-7xx10)=50`

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