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Solution :

The enectrostatic energy stored <br> `U=(1)/(2)(q^(2))/(C)=(q^(2))/(2epsilon_(0)A)xxd" …(i)"` <br> (where C is the capacitance, `C=(epsilon_(0)A)/(d)`, q is the charge upon capacitor) <br> Now the electric field in the space (between plates of capacitor) <br> `E=(q)/(epsilon_(0)A)" ...(ii)"` <br> From equation (i) and (ii), <br> `U=(1)/(2)((q)/(epsilon_(0)A))^(2)xxepsilon_(0)xxAxxd` <br> `rArr" "U=(1)/(2)epsilon_(0)E^(2)xx"Volume"` <br> Hence `(U)/("Volume")=(1)/(2)epsilon_(0)E^(2)" ...(iii)"` <br> This expression can be compared with magnetic energy per unit volume which is equal to `(B^(2))/(2mu_(0)).` ....(iv)