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Find the force required to move a train of 2000 quintals up an incline of 1 in 50 , with an acceleration of 2ms2 , the force of friction being 0.5 newton per quintal .

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Force of friction =0.5N per qunital
f=0.5×2000=1000N
m=2000 quintals=2000×100kg
sinθ=150,a=2m/s2
In moving up an inclined plane, force required against gravity
=mgsinθ=39200N
And force required to produce acceleration =ma=2000×100×2=40,0000N
Total force required =1000 + 39,200 + 40,0000
=440200N.

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Updated on:21/07/2023

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