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An indian submarine is moving in the Arabian sea with constant velocity. To detect enemy it sends out sonar waves which travel with velocity 1050(m)/(s) in water. Initially the waves are getting reflected from a fixed island and the reflected waves are coming back to submarine. The frequency of reflected waves are detected by the submarine and found to be 10% greater than the sent waves. <br> Now an enemy ship comes in front, due to which the frequency of reflected waves detected by submarine becomes 21% greater than the sent waves. <br> Q If the wavelength received by enemy ship is lamda' and wavelength of reflected waves received by submarine is lamda'', then ((lamda')/(lamda'')) equals <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_VO6_C06_E01_139_Q01.png" width="80%">
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Answer Text
1`1.1``1.2`2
Answer :
BSolution :
`lamda'=(vw.r.t.observer)/(f')` <br> `=(v+v_2)/(f_0((v+v_2))/((v-50)))=(v-50)/(f_0)` <br>`lamda''=(v+50)/(f_0((v+v_2)(v+50))/((v-v_2)(v-50)))=((v-v_2)(v-50))/(f_0(v+v_2))` <br> `(lamda')/(lamda'')=(v+v_2)/(v-v_2)=(1050+50)/(1050-50)=1.1` 
