logo
or
search
upload

An indian submarine is moving in the Arabian sea with constant velocity. To detect enemy it sends out sonar waves which travel with velocity 1050(m)/(s) in water. Initially the waves are getting reflected from a fixed island and the reflected waves are coming back to submarine. The frequency of reflected waves are detected by the submarine and found to be 10% greater than the sent waves. <br> Now an enemy ship comes in front, due to which the frequency of reflected waves detected by submarine becomes 21% greater than the sent waves. <br> Q If the wavelength received by enemy ship is lamda' and wavelength of reflected waves received by submarine is lamda'', then ((lamda')/(lamda'')) equals <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_VO6_C06_E01_139_Q01.png" width="80%">

Apne doubts clear karein ab Whatsapp par bhi. Try it now.
CLICK HERE

Loading DoubtNut Solution for you

Watch 1000+ concepts & tricky questions explained!

21.3 K+ views | 1.1 K+ people like this

   
Share
Share

Answer Text

1`1.1``1.2`2

Answer :
B
Solution :
`lamda'=(vw.r.t.observer)/(f')` <br> `=(v+v_2)/(f_0((v+v_2))/((v-50)))=(v-50)/(f_0)` <br>`lamda''=(v+50)/(f_0((v+v_2)(v+50))/((v-v_2)(v-50)))=((v-v_2)(v-50))/(f_0(v+v_2))` <br> `(lamda')/(lamda'')=(v+v_2)/(v-v_2)=(1050+50)/(1050-50)=1.1`

Related Video

1:42

29.6 K+ Views | 1.5 K+ Likes

5:54

102.8 K+ Views | 5.1 K+ Likes

5:38

98.0 K+ Views | 50.5 K+ Likes

3:28

5.4 K+ Views | 700+ Likes

80.1 K+ Views | 8.2 K+ Likes

4.7 K+ Views | 200+ Likes

1:20

900+ Views | 49 Likes

bottom open in app