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An indian submarine is moving in the Arabian sea with constant velocity. To detect enemy it sends out sonar waves which travel with velocity 1050(m)/(s) in water. Initially the waves are getting reflected from a fixed island and the reflected waves are coming back to submarine. The frequency of reflected waves are detected by the submarine and found to be 10% greater than the sent waves. <br> Now an enemy ship comes in front, due to which the frequency of reflected waves detected by submarine becomes 21% greater than the sent waves. <br> Q. The speed of indian submarine is <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_VO6_C06_E01_137_Q01.png" width="80%">

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Answer Text

`10(m)/(s)``50(m)/(s)``100(m)/(s)``20(m)/(s)`

Answer :
B
Solution :
<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_VO6_C06_E01_137_S01.png" width="80%"> <br> `f'=f_0((v+v_1)/(v-v_1))`,`v=1050` <br> `f'=(110f_0)/(100)` <br> Solve to get `v_1=50(m)/(s)`

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