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Solution :

(a) `lambda =( c) /(f) = (3 xx 10^(8) ) /(3 xx 10^(10)) = 1 xx 10^(-2) m` <br> (b) `K = (2pi)/(lambda) =(2xx 3.14)/(10^(-2) ) = 6.28 xx 10^(2) 6= 628 m^(-1)` <br> (c) `E = CB_(0) sin(2pi xx 3 xx 10^(10) t - 628 x) overset(^)(j) (N)/(C )` <br> and `bar(B) = 1 xx 10^(-7) sin (6pi xx 10^(10) t - 628 x) overset(^)(k) T`