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An 8 cm long wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. If the magnetic field inside the solenoid is 0.3 T, then magnetic force on the wire is

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Answer Text

0.14N0.24N0.34N0.44N

Answer :
B
Solution :
`F=Il B sin theta` <br> Here, `theta=90^(@),I=10A,` <br> `l= 8cm = 8xx10^(-2)m, B=0.3T` <br> `therefore" "F=10xx8xx10^(-2)xx0.3xxsin 90^(@)=0.24N`

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