A soild sphere is initially kept in open air, and the pressure exerted on it by air is $1.0\times {10}^{5}N/m^2$ (atmospheric pressure). The sphere is lowered into the ocean to a depth where the pressure is 200 times the atmospheric pressure. The volume of the sphere in air is $0.5m^3$. What is the change in the volume once the sphere is submerged ? Given that bulk modulus is $6.1\times {10}^{10}N/m^2$.

The volume of a solid is $6\times {10}^{-3}{m}^3$ under 2 atm pressure. Find the change in volume when subjected to a pressure of 102 atm. Bulk modulus of the material $={10}^{11}N{m}^{-2}$.

The bulk modulus of a liquid is $2\times {10}^{10}N/m^2$. What is the percentage decrease in the volume of the liquid, when the pressure is increased by 20 atmosphere?
(one atmosphere $={10}^{5}N/m^2$)

A metal block is experiencing an atmospheric pressure of $1\times {10}^{5}N/m^2$, when the same block is placed vacuum chamber, the freactional change in its volume is (the bulk modulus of metal is $1.25\times {10}^{11}N/m^2$)

A metal block is experiencing an atmospheric pressure of $1\times {10}^{5}N/m^2$, when the same block is placed vacuum chamber, the freactional change in its volume is (the bulk modulus of metal is $1.25\times {10}^{11}N/m^2$)

A metal block is experiencing an atmospheric pressure of $1\times {10}^{5}N/m^2$, when the same block is placed vacuum chamber, the freactional change in its volume is (the bulk modulus of metal is $1.25\times {10}^{11}N/m^2$)

One bar is equivalent of ${10}^{5}N/m^2$. The atmosphere pressure is $1.0313\times {10}^{5}N/m^2$. The same in bar is

The pressure required to reduce the given volume of water by $1\%$ is,
(Bulk modulus of water $=2\times {10}^{9}N/m^2$)

The bulk modulus of elasticity of the material of a metal sphere is $2\times {10}^{11}N/m^2$. In open air, atmospheric pressure of ${10}^{5}N/m^2$ acts on it. What is the fractional change in its volume if it is kept in a vacuum chamber ?

A solid sphere of radius 0.2 m is subjected to a uniform pressure of ${10}^{5}N/m^2$. If the bulk modulus of the material is $1.6\times {10}^{11}N/m^2$, then the decrease in the volume of the sphere is approximately will be

Ten litre of water is compressed by an increase in pressure of 10 atmosphere. If the compressibility of water is $5\times {10}^{-10}{m}^2/N,$ then the change in volume of water will be (one atmosphere $={10}^{5}N/m^2).$