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A network of four each of 12 mu F capacitance is connected to a 500 V apply as shown in Fig. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_XII_V01_C01_E01_218_Q01.png" width="80%"> <br> (a) Equivalent capacitance of the network. <br> (b) Charge on each capacitor.

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Answer Text

Answer :
(a) `16 muF` (b) `q_(1) = q_(2) = q_(3) = 2000 muC, q_(4) = 6000 muC`
Solution :
Here, `C_(1), C_(2), C_(3)` are in series. <br> `C_(123) = (12 muF)/(3) = 4 muF` <br> As `C_(4)` is in parallel with this combination, <br> `:. C_(eq) = 4+12 = 16 muF` <br> `q_(1) = q_(2) = q_(3) = C_(123) V = 4 muF xx 500 = 2000 muC` <br> `q_(4) = C_(4) V = 12 muF xx 500 V = 6000 muC`

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