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For Car `A` <br> `u = 54 km//h = (54 xx 1000 m)/(60 xx 60 s) = 15 m//s` <br> `v = 0, t = 4 sec`. <br> For Car `B` <br> `u = 36 km//h = (36 xx 1000 m)/(60 xx 60 s) = 10 m//s` <br> The speed time graphs for cars `A` and `B` are as hsown in Fig. <br> Distance travelled by A before stopping <br> `s_(1) =` area under vel. time graph of `A = (15 xx 4)/(2) = 30 m` <br> Distance travelled by B before stopping <br> `s_(2) =` area under vel. time graph of `B = (10 xx 6)/(2) = 30 m` <br> Clearly, `s_(1) = s_(2)` <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_IX_V01_C01_E01_100_S01.png" width="80%">