A charge of 8 mC is located at the origin. Calculate the work done in taking a small charge of $- 2 \times 10^{- 9}$ from a point P(0,0,3cm) to a point Q (0,4cm,0) via a point R(0,6cm,9cm).

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Updated on:21/07/2023

Class 12 PHYSICS ELECTROSTATICS

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Calculate the work done in taking a charge $- 2 \times 10^{- 9}$ C from A to B via C (in diagram )

A0.2 joule
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As per this diagram a point charge $+ q$ is placed at the origin $O$ . Work done in taking another point charge $- Q$ from the point $A (0, a)$ to another point $B (a, 0)$ along the staight path $A B$ is:

A $(\frac{- q Q}{4 π ε_{0}} \frac{1}{a^{2}}) \sqrt{2 a}$
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C $(\frac{q Q}{4 π ε_{0}} \frac{1}{a^{2}}) \frac{1}{\sqrt{2}}$
D $(\frac{q Q}{4 π ε_{0}} \frac{1}{a^{2}}) \frac{1}{\sqrt{2 a}}$
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As per this diagram a point charge $+ q$ is placed at the origin $O$ . Work done in taking another point charge $- Q$ from the point $A (0, a)$ to another point $B (a, 0)$ along the staight path $A B$ is:

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B $(- q Q / 4 π ε 0) (1 / a 2) \sqrt{} 2 a$
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