A certain transverse sinusoidal wave of wavelength 20 cm is moving in the positive x direction. The transverse velocity of the particle at x=0 as a function of time is shown. The amplitude of the motion is:
5πcm
π2cm
10πcm
2πcm
The correct Answer is:c
Vmax=Aω=5⇒A2π4=5
⇒A=10πcm
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Knowledge Check
- Question 1 - Select One
A transverse sinusoidal wave of wavelength 20 cm is moving along a string towards increasing x. the transverse displacement of the string particle at x=0 as a function of time is shown in figure.
Q. The velocity of propagation of the wave is ?A2cm/sB4cm/sC1cm/sD8cm/s - Question 1 - Select One
A transverse sinusoidal wave of wavelength 20 cm is moving along a string towards increasing x. the transverse displacement of the string particle at x=0 as a function of time is shown in figure.
Q. Skecth of one wavelength of the wave (the portion between x=0 and x=20cm) at time t=0 is:A
B
C
D
- Question 1 - Select One
A transverse sinusoidal wave of wavelength 20 cm is moving along a string towards increasing x. the transverse displacement of the string particle at x=0 as a function of time is shown in figure.
Q. The transverse velocity of the particle at x=0 at t=5.0 s is ?A−2cm/sB+2cm/sC+1.5cm/sD−2.5cm/s - Question 1 - Select One
A transverse sinusoidal wave of wavelength 20 cm is moving along a string towards increasing x. The transverse displacement of the string particle at as a function of time is shown in Figure.
The equation of the wave with all the constants evaluated is:
Ay=(4.0cm)sin(π10x−π5t),x in cm and t in sec.By=(4.0cm)sin(π10x+π5t),x in cm and t in secCy=(4.0cm)sin(π10x−π5t+π), x in cm and t in secDy=(4.0cm)cos(π10x−π5t+π),x in cm and t in sec - Question 1 - Select One
A transverse sinusoidal wave moves along a string in the positive x-direction at a speed of 10cm/s. The wavelength of ythe wave is 0.5m and its amplitude is 10cm. At a particular time t, the snap-shot of the wave is shown in figure. The velocity of point P when its displacement is 5cm is -
A(a) √350ˆJm/sB(b) −√350ˆJm/sC( c ) √350ˆim/sD(d) −√350ˆim/s
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