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A car moving at 160 km//h when passes the mark-A, driver applies brake and reduces its speed uniformly to 40 km//h at mark-C. The mark are spaced at equal distances along the road as shown below. <br> At which part of the track the car has instantaneous speed of 100 km//h ? Neglect the size of the car. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/A2Z_XI_C03_E01_283_Q01.png" width="80%">

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Answer Text

A mark-BBetween mark-A and mark-Bbetween mark-B and mark-Cinsufficient information to decide.

Answer :
C
Solution :
From `A` to `C` : `(40)^2 - (160)^2 = 2a (AC)` <br> From `A` to `D` : `(100)^2 - (160)^2 = 2a (AD)` <br> Here `D` is the point where speed is `100 km//h`. <br> From above `AD = (13)/(20) (AC) and AB = (AC)/(2)` <br> We see that AD gt AB`.

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