A body is dropped from a height of $40m$. After it crosses half distance, the acceleration due to gravity ceases to act. The body will hit ground with velocity $(\text{Take}g=10m/s^2)$ :

A body is dropped from a height of 39.2 m. After it crosses half distance, the acceleration due to gravity ceases to act. The body will hit the ground with velocity ( Take $g=10m/s^2$ )

A melon is dropped from a height of 39.2 m. After it crosses through half that distance , the acceleration due to gravity is reduced to zero by air drag. With what velocity does the melon hit the ground ?

A body of mass 2 kg is dropped from a height of 1 m. It s kinetic as it reaches the ground is

A body falls freely from a height 'h' after two seconds if acceleration due to gravity is reversed the body

A body is dropped from a height of 40 m from the surface of the Earth. Its final velocity is 28 m $s^{-1}$. What would be the final velocity of the body, if it is dropped from the same height on another planet where the acceleration due to gravity is 2.5 m $s^{-2}$. Assume atmospheric conditions to be similar.
(Take earth = 10 m $s^{-2}$)

A balloon is rising up with an acceleration of 10$m/s^2$. A body is dropped from the balloon when its velocity is 200 $m/s$. The body strickes the ground in half a minute. With that velocity did the body hit the ground ? Take $g=9.8m/s^2$.

A body of mass 2 kg is dropped from rest from a height 20 m from the surface of Earth. The body hiys the ground with velocity 10 m/s, then work done $(g=10m/s^2)$

A cricket ball is dropped from a height of 20 meters.
(a) Calculate the speed of the ball when it hits the ground.
(b) Calculate the time it takes to fall though this height $(g=10m/s^2)$

A body falls freely from a height of 125 m $(g=10m/s^2)$. After 2 sec gravity ceases to act find time taken by it to reach the ground?

A body of mass 10 kg is dropped from a height of 20 m. (Take g = 10 $\frac{3}{s^2})$
Its kinetic energy when it hits the ground.