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A block of mass 1kg is pushed up a surface inclined to horizontal at an angle of 30 by a force of 10N parallel to the inclined surface [figure]. The coefficient of friction between block and the incline is 0.1. If the block is pushed up by 10 m along the incline, calculate
(a) work done against gravity
(b) work done against force of friction
(c) increase in potential energy
(d) increase in kinetic energy
(e) work done by applied force.
A block of mass 1kg is pushed up a surface inclined to horizontal at an angle of 30^(@) by a force of 10N parallel to the inclined surface [figure]. The coefficient of friction between block and the incline is 0.1. If the block is pushed up by 10 m along the incline, calculate   (a) work done against gravity   (b) work done against force of friction   (c) increase in potential energy   (d) increase in kinetic energy   (e) work done by applied force.

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In figure, f is the force of friction acting down the incline.
Here, m=1kg,θ=30
F=10N,μ=0.1,s=10m. (a) Work done against gravity
Wg=mgsinθ×s=1×10sin30×10=1002=50J
(b) Work done against friction
Wf=f×s=μR×s=μmgcosθ×s
=0.1×1×10cos30×10=10×0.866=8.66J
(c) Increase in P.E. =mgh=mg(ssinθ)=1×10×10sin30=50J
(d) Increase in K.E. =ΔK=?
Acceleration of block up the incline
a=F(mgsinθ+μmgcosθ)m=10(1×10×12+0.1×10×0.866)1=4.13m/s2
From υ2u2=2as
ΔK=12m(υ2u2)=12m×2as=mas=1×4.13×10=41.3J
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Updated on:21/07/2023

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