A ball of mass m moving with velocity v collides head-on which the second ball of mass m at rest. I the coefficient of restitution is e and velocity of first ball after collision is v1 and velocity of second ball after collision is v2 then
v1=(1−e)u2,v2=(1+e)u2
v1=(1+e)u2,v2=(1−e)u2
v1=u2,v2=−u2
v1=(1+e)u,v2=(1−e)u
The correct Answer is:A
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