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`C_(n et)=(C_1C_2)/(C_1+C_2)=2/3muF` <br> `q_(n et)=C_(n et)V` <br> `=(2/3muF)(1200V)` <br> `=800muC` <br> In series `q` remains same. <br> `:. q_1=q_2=800muC` <br> `V_1=q_1/C_1=800V` <br> and `V_2=q_2/C_2=400V` <br> b. Now, total charge will become `1600muC`. This will now distribute in direct ratio of capacity. <br> `:.q_1/q_2=C_1/C_2=1/2` <br> `q_1=(1/3)=(1600)=1600/3muC` <br> `q_2=(2/3)(1600)=((3200)/3)muC` <br> They will have a common potential (in parallel) given by <br> `V=("Total charge")/("Total capacity")` <br> `=(1600muC)/(3muF)` <br> `=1600/3V` Related Video

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