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A 120V,60Hz a.c. power is connected 800Ω non-inductive resistance and unknown capacitance in series. The voltage drop across the resistance is found to be 102V, then voltage drop across capacitor is

A

8V

B

102V

C

63V

D

55V

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Text Solution
Verified by Experts

The correct Answer is:3


V2=V2R+V2C
V2C=V2V2R
V2C=(120)2(102)2
VC=63V

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Updated on:21/07/2023

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