A 120V,60Hz a.c. power is connected 800Ω non-inductive resistance and unknown capacitance in series. The voltage drop across the resistance is found to be 102V, then voltage drop across capacitor is
8V
102V
63V
55V
The correct Answer is:3
V2=V2R+V2C
V2C=V2−V2R
V2C=(120)2−(102)2
VC=63V
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