Write the ascending order of the distance between the parallel lines
(A) ${\displaystyle 2x+3y+1=0,2x+3y+14=0}$
(B) ${\displaystyle 3x+4y+10=0,3x+4y+5=0}$
(C) ${\displaystyle x+y+1=0,x+y+3=0}$
(D) ${\displaystyle 2x+y+1=0,2x+y+6=0}$ Solution in Telugu

Match the following
$\begin{array}{cc}\text{Line}& \text{Slope}\\ I.33x-3y-38=0& \left(a\right)-2/3\\ II.4x-y-2=0& \left(b\right)4\\ III.2x+3y-6=0& \left(c\right)-2/13\\ IV.2x+25y=1& \left(d\right)11\\ & \left(e\right)-2/25\end{array}$

A : The equation of the line passing through (1, 2) with slope $2/5$ is $2x-5y+8=0$
R : The equation of the line passing through $(x_1,y_1)$ with slope m is $y-y_1=m(x-x_1)$

The equation of the line perpendicular to the line $2x+3y-5=0$ and passing through (3, -4) is

Which of the following is an empt set

A : If $x^2+y^2-2x+3y+k=0,x^2+y^2+8x06y-7=0$ cut each other orthogonally then k = 10 .
R : The circles $x^2+y^2+2gx+2fy+c=0,x^2+y^2+2g\text{'}x+2f\text{'}y+c\text{'}=0$ cut each other orthogonally iff $2gg\text{'}+2ff\text{'}=c+c\text{'}$

The equation of a straight line passing through (3, 2) and cutting an intercept of 2 units between the lines $3x+4y=11\text{and}3x+4y=1$ is (A) $2x+y-8=0$ (B) $3y-4x+6=0$ (C) $3x+4y-17=0$ (D) $2x-y-4=0$

Consider the triangle formed by the lines
y+3x+2=0, 3y-2x-5=0, 4y+x-14=0
Match the following lists:

उस सरल रेखा का समीकरण निकालें जो $x-y-1=0$ और $2x-3y+1=0$ के छेदन-बिंदु से होकर जाती है और $3x+4y=14$ के समान्तर है।

उस सरल रेखा का समीकरण निकालें जो x-y-1 = 0 और 2x -3y + 1 = 0 के छेदन-बिंदु से होकर जाती है और 3x+4y = 14 के समांतर है।

For the circle $x^2+y^2-2x-4y-4=0$, then lines 2x+3y-1=0, 2x+y+5=0 are

For the circle $x^2+y^2-2x-4y-4=0$, then lines 2x+3y-1=0, 2x+y+5=0 are

The lines parallel to the normal to the curve $xy=1$ is/are $3x+4y+5=0$ (b) $3x-4y+5=0$ $4x+3y+5=0$ (d) $3y-4x+5=0$

The lines parallel to the normal to the curve $xy=1$ is/are (a)$3x+4y+5=0$ (b) $3x-4y+5=0$ (c)$4x+3y+5=0$ (d) $3y-4x+5=0$

Write the ascending order of the distance between the parallel lines
(A) $2x+3y+1=0,2x+3y+14=0$
(B) $3x+4y+10=0,3x+4y+5=0$
(C) $x+y+1=0,x+y+3=0$
(D) $2x+y+1=0,2x+y+6=0$

Find the equation of the line passing through the intersection of 2x-y-1 = 0 and 3x-4y+6 = 0 and parallel to the line x + y -2 = 0 .