Two different packs of cards are shuffled together. Cards dealt equally among 4 players, each getting 13 cards. The number of ways in which a player get his cards if no two cards are from the same suit with the same denomination is

A

$^{52} C_{13}$

B

$2^{13}$

C

$^{52} P_{13}$

D

$^{52} C_{13} \times 2^{13}$

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Here, we have 52 cards, each card being 2 in number. It is given that no two are to be of the same suit with the same denomination. So, we first draw 13 cards from 52 cards. This can be done in $^{52} C_{13}$ ways. Now each of 13 cards selected can be chosen in 2 ways either from first pack or from 2nd pack.
Hence, required number of ways $=^{52} C_{13} \times 2^{13}$ .

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Updated on:21/07/2023

Class 11 MATHS PERMUTATIONS AND COMBINATIONS

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