Two different packs of cards are shuffled together. Cards dealt equally among 4 players, each getting 13 cards. The number of ways in which a player get his cards if no two cards are from the same suit with the same denomination is
52C13
213
52P13
52C13×213
Here, we have 52 cards, each card being 2 in number. It is given that no two are to be of the same suit with the same denomination. So, we first draw 13 cards from 52 cards. This can be done in 52C13 ways. Now each of 13 cards selected can be chosen in 2 ways either from first pack or from 2nd pack.
Hence, required number of ways =52C13×213.
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