The vertex of ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1$ are :

$(\pm 5, 0)$

$(\pm 4, 0)$

$(0, \pm 5)$

$(0, \pm 4)$

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The correct Answer is:C

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Step by step video, text & image solution for The vertex of ellipse (x^(2))/(16)+(y^(2))/(25)=1 are : by Maths experts to help you in doubts & scoring excellent marks in Class 11 exams.

Updated on:21/07/2023

Class 11 MATHS PARABOLA

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Similar Practice Problems

Question 1 - Select One
If $e_{1}$ is the eccentricity of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{25}$ =1 and $e_{2}$ is the eccentricity of the hyperbola passing through the foci of the ellipse and $e_{1} e_{2} = 1$ then equation of the hyperbola is
A $\frac{x^{2}}{9} - \frac{u y^{2}}{16} = 1$
B $\frac{x^{2}}{16} - \frac{y^{2}}{9} = - 1$
C $\frac{x^{2}}{9} - \frac{y^{2}}{25} = 1$
Dnone of these
Question 1 - Select One
If $e_{1}$ is the eccentricity of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1 and e_{2}$ is the eccentricity of the hyperbola passing through the foci of the ellipse and $e_{1} e_{2} = 1,$ then the equation of the hyperbola is
A $\frac{x^{2}}{9} - \frac{y^{2}}{16} = 1$
B $\frac{x^{2}}{16} - \frac{y^{2}}{9} = - 1$
C $\frac{x^{2}}{9} - \frac{y^{2}}{25} = 1$
DNone of these
Question 1 - Select One
If the foci of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{b^{2}} = 1$ and the hyperbola $\frac{x^{2}}{144} - \frac{y^{2}}{81} = \frac{1}{25}$ coincide write the value of $b^{2} .$
A1
B5
C7
D9
Question 1 - Select One
If the foci of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{b^{2}} = 1$ and the hyperbola $\frac{x^{2}}{144} - \frac{y^{2}}{81} = \frac{1}{125}$ coincide, the find the value of $b^{2}$ .
A1
B5
C7
D9

The vertex of ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1$ are :

The correct Answer is:C

Related Playlists

Similar Practice Problems

If $e_{1}$ is the eccentricity of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{25}$ =1 and $e_{2}$ is the eccentricity of the hyperbola passing through the foci of the ellipse and $e_{1} e_{2} = 1$ then equation of the hyperbola is

If $e_{1}$ is the eccentricity of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1 and e_{2}$ is the eccentricity of the hyperbola passing through the foci of the ellipse and $e_{1} e_{2} = 1,$ then the equation of the hyperbola is

If the foci of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{b^{2}} = 1$ and the hyperbola $\frac{x^{2}}{144} - \frac{y^{2}}{81} = \frac{1}{25}$ coincide write the value of $b^{2} .$

If the foci of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{b^{2}} = 1$ and the hyperbola $\frac{x^{2}}{144} - \frac{y^{2}}{81} = \frac{1}{125}$ coincide, the find the value of $b^{2}$ .

Similar Questions

NAGEEN PRAKASHAN-CONIC SECTION-Exercise 11F

The vertex of ellipse x216+y225=1 are :

The correct Answer is:C

Related Playlists

Similar Practice Problems

If e1 is the eccentricity of the ellipse x216+y225 =1 and e2 is the eccentricity of the hyperbola passing through the foci of the ellipse and e1e2=1 then equation of the hyperbola is

If e1 is the eccentricity of the ellipse x216+y225=1ande2 is the eccentricity of the hyperbola passing through the foci of the ellipse and e1e2=1, then the equation of the hyperbola is

If the foci of the ellipse x216+y2b2=1 and the hyperbola x2144−y281=125 coincide write the value of b2.

If the foci of the ellipse x216+y2b2=1 and the hyperbola x2144−y281=1125 coincide, the find the value of b2.

Similar Questions

NAGEEN PRAKASHAN-CONIC SECTION-Exercise 11F

The vertex of ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1$ are :

If $e_{1}$ is the eccentricity of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{25}$ =1 and $e_{2}$ is the eccentricity of the hyperbola passing through the foci of the ellipse and $e_{1} e_{2} = 1$ then equation of the hyperbola is

If $e_{1}$ is the eccentricity of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1 and e_{2}$ is the eccentricity of the hyperbola passing through the foci of the ellipse and $e_{1} e_{2} = 1,$ then the equation of the hyperbola is

If the foci of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{b^{2}} = 1$ and the hyperbola $\frac{x^{2}}{144} - \frac{y^{2}}{81} = \frac{1}{25}$ coincide write the value of $b^{2} .$

If the foci of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{b^{2}} = 1$ and the hyperbola $\frac{x^{2}}{144} - \frac{y^{2}}{81} = \frac{1}{125}$ coincide, the find the value of $b^{2}$ .