If $Im \frac{2 z + 1}{i z + 1} = - 2$ , then locus of z, is

a circle

a parabola

a straight line

none of these

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The correct Answer is:A

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Updated on:21/07/2023

Class 12 MATHS COMPLEX NUMBERS

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Similar Practice Problems

Question 1 - Select One
If 1m $(\frac{2 z + 1}{i z + 1}) = 3$ , then locus of z is
AA circle
BA parabola
CA straight line
DNone of these
Question 1 - Select One
If Im $(\frac{z - 1}{2 z + 1}) = - 4$ , then locus of z is
Aan ellipse
Ba parabola
Ca straight line
Da circle
Question 1 - Select One
If Real $(\frac{2 z - 1}{z + 1})$ =1, then locus of z is , where z=x+iy and $i = \sqrt{- 1}$
Acircle
Bparabola
CSt. line
DPair of ST. lines
Question 1 - Select One
The point 'z' in Argand's plane
Moves such that
Re $(\frac{i z + 1}{i z - 1}) = 2,$ then locus of z is -
AStraight line
Bcircle
Cellipse
Dhyperbola
Question 1 - Select One
If $l m (\frac{z - 1}{2 z + 1}) = - 4$ then locus of z is
AAn ellipse
BA parabola
CA straight line
DA circle
Question 1 - Select One
If the imaginary part of $\frac{2 z + 1}{i z + 1}$ is -4, then the locus of the point representing z in the complex plane is
Aa straight line
Ba parabola
Ca circle
Dan ellipse
Question 1 - Select One
If z=x+iy and real part $(\frac{z - 1}{2 z + 1}) = 1$ then locus of z is
AStraight line with slope 2
BStraight line with slope - $\frac{1}{2}$
Ccircle with diameter $\frac{\sqrt{5}}{2}$
Dcircle with diameter $\frac{1}{2}$
Question 1 - Select One
Statement-1 : The locus of z , if $a r g (\frac{z - 1}{z + 1}) = \frac{π}{2}$ is a circle.
and
Statement -2 : $∣ ∣ ∣ \frac{z - 2}{z + 2} ∣ ∣ ∣ = \frac{π}{2}$ , then the locus of z is a circle.
AStatement -1 is True, Statement -2 is True, Statement -2 is a correct explanation for statement -2
BStatement -1 is True, Statement -2 is True , Statement -2 is NOT a correct explanation for Statement -2
CStatement -1 is True, Statement -2 is False
DStatement -1 is Flase, Statement -2 is True

If $Im \frac{2 z + 1}{i z + 1} = - 2$ , then locus of z, is

The correct Answer is:A

Related Playlists

Similar Practice Problems

If 1m $(\frac{2 z + 1}{i z + 1}) = 3$ , then locus of z is

If Im $(\frac{z - 1}{2 z + 1}) = - 4$ , then locus of z is

If Real $(\frac{2 z - 1}{z + 1})$ =1, then locus of z is , where z=x+iy and $i = \sqrt{- 1}$

The point 'z' in Argand's plane
Moves such that
Re $(\frac{i z + 1}{i z - 1}) = 2,$ then locus of z is -

If $l m (\frac{z - 1}{2 z + 1}) = - 4$ then locus of z is

If the imaginary part of $\frac{2 z + 1}{i z + 1}$ is -4, then the locus of the point representing z in the complex plane is

If z=x+iy and real part $(\frac{z - 1}{2 z + 1}) = 1$ then locus of z is

Statement-1 : The locus of z , if $a r g (\frac{z - 1}{z + 1}) = \frac{π}{2}$ is a circle.
and
Statement -2 : $∣ ∣ ∣ \frac{z - 2}{z + 2} ∣ ∣ ∣ = \frac{π}{2}$ , then the locus of z is a circle.

Similar Questions

OBJECTIVE RD SHARMA-COMPLEX NUMBERS -Exercise

If Im2z+1iz+1=−2, then locus of z, is

The correct Answer is:A

Related Playlists

Similar Practice Problems

If 1m (2z+1iz+1)=3, then locus of z is

If Im(z−12z+1)=−4, then locus of z is

If Real (2z−1z+1)=1, then locus of z is , where z=x+iy and i=√−1

The point 'z' in Argand's plane Moves such that Re (iz+1iz−1)=2, then locus of z is -

If lm(z−12z+1)=−4 then locus of z is

If the imaginary part of 2z+1iz+1 is -4, then the locus of the point representing z in the complex plane is

If z=x+iy and real part (z−12z+1)=1 then locus of z is

Statement-1 : The locus of z , if arg(z−1z+1)=π2 is a circle. and Statement -2 : ∣∣∣z−2z+2∣∣∣=π2, then the locus of z is a circle.

Similar Questions

OBJECTIVE RD SHARMA-COMPLEX NUMBERS -Exercise

If $Im \frac{2 z + 1}{i z + 1} = - 2$ , then locus of z, is

If 1m $(\frac{2 z + 1}{i z + 1}) = 3$ , then locus of z is

If Im $(\frac{z - 1}{2 z + 1}) = - 4$ , then locus of z is

If Real $(\frac{2 z - 1}{z + 1})$ =1, then locus of z is , where z=x+iy and $i = \sqrt{- 1}$

The point 'z' in Argand's plane
Moves such that
Re $(\frac{i z + 1}{i z - 1}) = 2,$ then locus of z is -

If $l m (\frac{z - 1}{2 z + 1}) = - 4$ then locus of z is

If the imaginary part of $\frac{2 z + 1}{i z + 1}$ is -4, then the locus of the point representing z in the complex plane is

If z=x+iy and real part $(\frac{z - 1}{2 z + 1}) = 1$ then locus of z is

Statement-1 : The locus of z , if $a r g (\frac{z - 1}{z + 1}) = \frac{π}{2}$ is a circle.
and
Statement -2 : $∣ ∣ ∣ \frac{z - 2}{z + 2} ∣ ∣ ∣ = \frac{π}{2}$ , then the locus of z is a circle.