If ABCD is a square, then
$¯ ¯¯¯¯ ¯ A B + 2 ¯ ¯¯¯¯ ¯ B C + 3 ¯ ¯¯¯¯ ¯ C D + 4 ¯ ¯¯¯¯ ¯ D A$ =

4 $¯ ¯¯¯¯ ¯ A C$

3 $¯ ¯¯¯¯ ¯ A C$

2 $¯ ¯¯¯¯ ¯ C A$

$¯ ¯¯¯¯ ¯ A C$

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The correct Answer is:C

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Updated on:21/07/2023

Class 12 MATHS VECTOR ALGEBRA

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Question 1 - Select One
If ABCD is a square then,
$2 ¯ ¯¯¯¯ ¯ A B + 4 ¯ ¯¯¯¯ ¯ B C + 5 ¯ ¯¯¯¯ ¯ C D + 7 ¯ ¯¯¯¯ ¯ D A =$
A $2 ¯ ¯¯¯¯ ¯ B D$
B $3 ¯ ¯¯¯¯ ¯ C A$
C $5 ¯ ¯¯¯¯ ¯ D B$
D $2 ¯ ¯¯¯¯ ¯ A C$
Question 1 - Select One
If ABCDE is a pentagon, then $¯ ¯¯¯¯ ¯ A B + ¯ ¯¯¯¯ ¯ A E + ¯ ¯¯¯¯ ¯ B C + ¯ ¯¯¯¯ ¯ D C + ¯ ¯¯¯¯ ¯ E D =$
A $¯ ¯¯¯¯ ¯ A C$
B2 $¯ ¯¯¯¯ ¯ A C$
C2 $¯ ¯¯¯¯ ¯ A D$
D3 $¯ ¯¯¯¯ ¯ A D$
Question 1 - Select One
If ABCDE is a regular penatagon then :
$¯ ¯¯¯¯ ¯ A B + ¯ ¯¯¯¯ ¯ B C + ¯ ¯¯¯¯ ¯ A D + ¯ ¯¯¯¯ ¯ E D + ¯ ¯¯¯¯ ¯ A E =$
A $¯ ¯¯¯¯ ¯ A C - 2 ¯ ¯¯¯¯ ¯ D C$
B $3 ¯ ¯¯¯¯ ¯ A C - 2 ¯ ¯¯¯¯ ¯ D C$
C $¯ ¯¯¯¯ ¯ C A - ¯ ¯¯¯¯ ¯ D C$
D $3 ¯ ¯¯¯¯ ¯ A C - ¯ ¯¯¯¯ ¯ D C$
Question 1 - Select One
If diagonals of a parallelogram ABCD intersect each other in M, then $¯ ¯¯¯¯ ¯ O A + ¯ ¯¯¯¯ ¯ O B + ¯ ¯¯¯¯ ¯ O C + ¯ ¯¯¯¯ ¯ O D$ =
A $¯ ¯¯¯¯¯ ¯ O M$
B2 $¯ ¯¯¯¯¯ ¯ O M$
C3 $¯ ¯¯¯¯¯ ¯ O M$
D4 $¯ ¯¯¯¯¯ ¯ O M$
Question 1 - Select One
$Δ A B C$ is an isosceles triangle and $¯ ¯¯¯¯ ¯ A B = ¯ ¯¯¯¯ ¯ A C = 2 a$ unit, $¯ ¯¯¯¯ ¯ B C$ = a unit. Draw $A D ⊥ B C$ , and find the length of $¯ ¯¯¯¯ ¯ A D$ .
A $\sqrt{15}$ a unit
B $\frac{\sqrt{15}}{2}$ a unit
C $\sqrt{17}$ a unit
D $\frac{\sqrt{17}}{2}$ a unit

If ABCD is a square, then
$¯ ¯¯¯¯ ¯ A B + 2 ¯ ¯¯¯¯ ¯ B C + 3 ¯ ¯¯¯¯ ¯ C D + 4 ¯ ¯¯¯¯ ¯ D A$ =

The correct Answer is:C

Related Playlists

Similar Practice Problems

If ABCD is a square then,
$2 ¯ ¯¯¯¯ ¯ A B + 4 ¯ ¯¯¯¯ ¯ B C + 5 ¯ ¯¯¯¯ ¯ C D + 7 ¯ ¯¯¯¯ ¯ D A =$

If ABCDE is a pentagon, then $¯ ¯¯¯¯ ¯ A B + ¯ ¯¯¯¯ ¯ A E + ¯ ¯¯¯¯ ¯ B C + ¯ ¯¯¯¯ ¯ D C + ¯ ¯¯¯¯ ¯ E D =$

If ABCDE is a regular penatagon then :
$¯ ¯¯¯¯ ¯ A B + ¯ ¯¯¯¯ ¯ B C + ¯ ¯¯¯¯ ¯ A D + ¯ ¯¯¯¯ ¯ E D + ¯ ¯¯¯¯ ¯ A E =$

If diagonals of a parallelogram ABCD intersect each other in M, then $¯ ¯¯¯¯ ¯ O A + ¯ ¯¯¯¯ ¯ O B + ¯ ¯¯¯¯ ¯ O C + ¯ ¯¯¯¯ ¯ O D$ =

$Δ A B C$ is an isosceles triangle and $¯ ¯¯¯¯ ¯ A B = ¯ ¯¯¯¯ ¯ A C = 2 a$ unit, $¯ ¯¯¯¯ ¯ B C$ = a unit. Draw $A D ⊥ B C$ , and find the length of $¯ ¯¯¯¯ ¯ A D$ .

Similar Questions

MARVEL PUBLICATION-VECTORS-TEST YOUR GRASP

If ABCD is a square, then ¯¯¯¯¯¯AB+2¯¯¯¯¯¯BC+3¯¯¯¯¯¯CD+4¯¯¯¯¯¯DA =

The correct Answer is:C

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Similar Practice Problems

If ABCD is a square then, 2¯¯¯¯¯¯AB+4¯¯¯¯¯¯BC+5¯¯¯¯¯¯CD+7¯¯¯¯¯¯DA=

If ABCDE is a pentagon, then ¯¯¯¯¯¯AB+¯¯¯¯¯¯AE+¯¯¯¯¯¯BC+¯¯¯¯¯¯DC+¯¯¯¯¯¯ED=

If ABCDE is a regular penatagon then : ¯¯¯¯¯¯AB+¯¯¯¯¯¯BC+¯¯¯¯¯¯AD+¯¯¯¯¯¯ED+¯¯¯¯¯¯AE=

If diagonals of a parallelogram ABCD intersect each other in M, then ¯¯¯¯¯¯OA+¯¯¯¯¯¯OB+¯¯¯¯¯¯OC+¯¯¯¯¯¯OD =

ΔABC is an isosceles triangle and ¯¯¯¯¯¯AB=¯¯¯¯¯¯AC=2aunit, ¯¯¯¯¯¯BC = a unit. Draw AD⊥BC, and find the length of ¯¯¯¯¯¯AD .

Similar Questions

MARVEL PUBLICATION-VECTORS-TEST YOUR GRASP

If ABCD is a square, then
$¯ ¯¯¯¯ ¯ A B + 2 ¯ ¯¯¯¯ ¯ B C + 3 ¯ ¯¯¯¯ ¯ C D + 4 ¯ ¯¯¯¯ ¯ D A$ =

If ABCD is a square then,
$2 ¯ ¯¯¯¯ ¯ A B + 4 ¯ ¯¯¯¯ ¯ B C + 5 ¯ ¯¯¯¯ ¯ C D + 7 ¯ ¯¯¯¯ ¯ D A =$

If ABCDE is a pentagon, then $¯ ¯¯¯¯ ¯ A B + ¯ ¯¯¯¯ ¯ A E + ¯ ¯¯¯¯ ¯ B C + ¯ ¯¯¯¯ ¯ D C + ¯ ¯¯¯¯ ¯ E D =$

If ABCDE is a regular penatagon then :
$¯ ¯¯¯¯ ¯ A B + ¯ ¯¯¯¯ ¯ B C + ¯ ¯¯¯¯ ¯ A D + ¯ ¯¯¯¯ ¯ E D + ¯ ¯¯¯¯ ¯ A E =$

If diagonals of a parallelogram ABCD intersect each other in M, then $¯ ¯¯¯¯ ¯ O A + ¯ ¯¯¯¯ ¯ O B + ¯ ¯¯¯¯ ¯ O C + ¯ ¯¯¯¯ ¯ O D$ =

$Δ A B C$ is an isosceles triangle and $¯ ¯¯¯¯ ¯ A B = ¯ ¯¯¯¯ ¯ A C = 2 a$ unit, $¯ ¯¯¯¯ ¯ B C$ = a unit. Draw $A D ⊥ B C$ , and find the length of $¯ ¯¯¯¯ ¯ A D$ .