If $A=\left[\begin{array}{cc}7& -3\\ 1& 4\end{array}\right]\text{and}B=\left[\begin{array}{c}5\\ 2\end{array}\right]$ solve for X when AX=B.

Let $A=\left[\begin{array}{ccc}1& 2& 3\\ 0& 1& 0\end{array}\right]\text{and}B=\left[\begin{array}{ccc}-1& 4& 3\\ 1& 0& 0\end{array}\right]$ Find 2A +3B.

If $A=\left[\begin{array}{ccc}-3& 1& 6\\ 2& -5& 0\\ 1& -3& 4\end{array}\right],B=\left[\begin{array}{cc}4& 7\\ -4& 2\\ -1& -5\end{array}\right]$ and AX=B, then the size of X is

Use A $A=[-2,-1,5,9]\text{and}B=\left[\begin{array}{cc}0& -5\\ 3& -2\\ 4& 0\\ -6& 1\end{array}\right]$for question 4
The product AB =

If $A=\{x:x^2-2x+2>0\}\text{and}B=\{x:x^2-4x+3\le 0\}$
A - B equals

Solve for matrics A and B , where
$2A+B=\left[\begin{array}{cc}3& -4\\ 2& 7\end{array}\right]\text{and}A-2B=\left[\begin{array}{cc}4& 3\\ 1& 1\end{array}\right]$

If $A=\left(\begin{array}{ccc}2& 2& -4\\ -4& 2& -4\\ 2& -1& 5\end{array}\right)\text{and}B=\left(\begin{array}{ccc}1& -1& 0\\ 2& 3& 4\\ 0& 1& 2\end{array}\right)$, find AB. Hence, solve the following equations $x-y=3,2x+3y+4z=17$ and y+2z=7

" Solve : $\frac{3x}{4}-\frac{2x+5}{3}=\frac{5}{2}$

(i) Let $A=\{x:x\in N,2\le x\le 6\}\text{and}B=(2,3,4,5,6),thenA=B$
(ii) Let $A=(1,3,5)\text{and}B=(3,5,1)\text{then}A=B$
Let $A=\{1,2,3\}\text{and}B=\{1,1,3,2,3\}\text{then}A=B$

If $x=\frac{5}{3}$ and $x=-\frac{1}{2}$ are the zeroes of the polynomial $a{x}^2-7x+b$, then find the values of a and b.

The algebraic sum of distances of the line $ax+by+2=0$ from $(1,2),(2,1)\text{and}(3,5)$ is zero and the lines $bx-ay+4=0$ and $3x+4y+5=0$ cut the coordinate axes at concyclic points. Then (a) $a+b=-\frac{2}{7}$ (b) area of triangle formed by the line $ax+by+2=0$ with coordinate axes is $\frac{14}{5}$ (c) line $ax+by+3=0$ always passes through the point $(-1,1)$ (d) max $\{a,b\}=\frac{5}{7}$