Given that the system of equations $3x+ky=1$ and $6x+3y=2$ . For what value of k does this system have infinite solutions ?

$4x+6y=12$
$y=80-kx$
For what value of k does the system of equation above have no solution?

$cx-5y=6$
$2x-3y=8$
In the system of equations above, c is a constant and x and y are variables. For what values of c will the system have no solutions?

−3x + y = 6
ax + 2y = 4
In the system of equations above, a is a constant. For which of the following values of a does the system have no solution?

For what value of k, the system of equations x - 3y = 5 and 2x - 6y = k has at most one solution?

$3x+4y=7$
$kx-2y=1$
For what value of k will the above system of equations have no solution?

For what value of k, the system of equations x - 3y = 5 and 2x - 5y = k has at most one solution?

For what value of k, the system of equations x - 3y = 5 and 2x - ky = 10 has at most one solution?

$kx-3y=4$
$4x-5y=7$
In the system of equations above, k is a constant and x and y are variables. For what value of k will the system of equations have no solution?

For what value of k, the system of equations 3x - 2y = 5 and 6x - ky = 8 has no unique solution?

Find the value of k for which the system of equations 2x + ky = 1 and 3x - 5y = 7 has a unique solution.