Function f(x)=x3−27x+5 is monotonically increasing when (a) x<−3 (b) |x|>3 (c) x≤−3 (d) |x|≥3
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Answeris D)
f(x)=x3−27x+5 monotonically increasing
f′(x)=3x2−27
f′(x)>0for monotically increasing
⇒3{x}2−27>0
x2−9>0
(x+3)(x−3)>0
Drawing its sign scheme, we have
⇒|x|≥3.
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Updated on:21/07/2023
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