For the triangle whose sides are $x+y-6=0,7x+y-6=0\text{and}x-7y=6$, the co-ordinates of the incentre are:

Incentre of the triangle whose vertices are (6, 0), (0, 6) and (7, 7), is

Three sides of a triangle are represented by the equation $x+y-6=0,2x+y-4=0\text{and}x+2y-5=0.$ The co-ordinate of its orthocentre of

A triangle is formed by the lines whose equations are $AB:x+y-5=0,BC:x+7y-7=0,\text{and}CA:7x+y+14=0$. Find the bisector of the interior angle at B

A triangle is formed by the lines whose equations are $AB:x+y-5=0,BC:x+7y-7=0,\text{and}CA:7x+y+14=0$. Find
the bisector of the exterior angle at C.

Orthocentre of the triangle whose sides are given by 4x - 7y + 10= 0, x + y - 5 = 0 & 7x + 4y - 15 = 0 is

The orthocentre of the triangle formed by the lines $x-7y+6=0,2x-5y-6=0\text{and}7x+y-8=0$ is

The orthocentre of the triangle formed by the lines $x-7y+6=0,2x-5y-6=0\text{and}7x+y-8=0$ is

The equation x+2y=3,y-2x=1 and 7x-6y+a=0 are consisten for

The equation x+2y=3,y-2x=1 and 7x-6y+a=0 are consisten for

The radical centre of three circles described on the three sides
$4x-7y+10=0,x+y-5=0\text{and}7x+4y-15=0$ of a triangle as diameters is