Find the products: $(\frac{3}{x} - 2 x^{2}) (\frac{9}{x^{2}} + 4 x^{4} + 6 x)$

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we know that,
$a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$
using this formula,
we can write it as,
$(\frac{3}{x} - 2 x^{2}) (\frac{9}{x^{2}} + 4 x^{4} + 6 x)$
$= {(\frac{3}{x})}^{3} - {(2 x^{2})}^{3}$
$= \frac{27}{x^{3}} - 8 x^{6}$

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Updated on:21/07/2023

Class 9 MATHS POLYNOMIALS

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