Find the equation of the circle which passes through the points (1,3)and(2,−1), and has its centre on the line 2x+y−4=0
The correct Answer is:x2+y2−3x−2y−1=0
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- Question 1 - Select One
What is the equation of the circle which passes through the points (3 , -2) and (-2,0) and having its centre on the line 2x + y - 3 =0 ?
Ax2+y2+3x+2=0Bx2+y2+3x+12y+2=0Cx2+y2+2x=0Dx2+y2=5 - Question 1 - Select One
The equation of the circle which passes through the points (2,3)and(4,5) and the centre lies on the straight line y−4x+3=0, is
Ax2+y2−4x−10y+25=0Bx2+y2−4x−10y−25=0Cx2+y2−4x+10y−25=0DNone of the above
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