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Find an angle theta (i) Which increases twice as fast as its cosine. (ii) Whose rate of increase twice is twice the rate of decrease of its consine.

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Answer Text

Solution :
(i) Here, `(d theta)/dt = 2 d/dt(costheta)`<br> `=> (d theta)/dt = -2sintheta (d theta)/dt`<br> `=>sin theta = -1/2`<br> `=> theta = (7pi)/6`.<br><br> (ii) Here, `(d theta)/dt = -2 d/dt(costheta)`<br> `=> (d theta)/dt = 2sintheta (d theta)/dt`<br> `=>sin theta = 1/2`<br> `=> theta = pi/6`.<br><br>

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