A coin is tossed 10 times. Find the probability of getting
(i) 2 Heads
(ii) Even numbers of heads
(i) Total no. of outcomes when coin is tossed 10 times is 210=1024
When 2 heads are there, this mean 8 tails also there.
i.e. we want the no. of ways in which
HHTTTTTTTT can be arranged is 10!2!8!=45
required probability =451024
(ii) (0 heads and 10 tails) or (2 heads and 8 tails) or (4 heads and 6 tails) or ( 6 heads and 4 tails) or (8 heads and 2 tails) or 10 heads and 10 tails0
=10!0!10!+10!2!8!+10!4!6!+10!8!2!+10!10!0!210
10C0+10C2+10C4+10C6+10C8+10C10210=210−1210
29210=12
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