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The pH of 2.5xx10^(-1) mol dm^(-3) HCN (aq) (K_(a)=4xx10^(-10)) is :

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Answer Text

`2xx10^(-5)` `2.0``4.7``5.0`

Answer :
D
Solution :
`[H^(+)]=sqrt(K_(a)xx c)` <br> `= sqrt(4xx10^(-10)xx2.5xx10^(-1))` <br> `=10^(-5)` <br> `pH=-log [H^(+)]=-log(10^(-5))=5`.

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